For Loop returns only first colum

[dUbbsNIX]

Here is my problem.

I create a .lst file containing the following:

-rw-rw-r-- 1 dvpears prism 19040 Sep 25 10:56 dax_e_ic_20030828.csv
-rw-rw-r-- 1 dvpears prism 19042 Sep 25 10:56 dax_e_ic_20030829.csv
-rw-rw-r-- 1 dvpears prism 71 Sep 25 10:56 dax_e_in_20030828.csv
-rw-rw-r-- 1 dvpears prism 71 Sep 25 10:56 dax_e_in_20030829.csv

Then I want to cycle through the contents of the .lst file, record by record, assigning each column into a variable.

My loop would be:
for rec in $(cat $LIVE_WORK/serverfiles.lst)
do
.
.
.

The problem I have is that for the 1st row in the .lst file, $rec is returning the following:
-rw-rw-r--
instead of
-rw-rw-r-- 1 dvpears prism 19040 Sep 25 10:56 dax_e_ic_20030828.csv

I think it is because of the spaces between each data item. How do I get the whole row assigned in $rec?

Any help greatly appreciated.

 

[Ygor]

Try...

while read rec
do
:
done < $LIVE_WORK/serverfiles.lst

 

[PHV]

Try something like this:
savIFS=&quot;$IFS&quot;;IFS=$(echo &quot;\n\r&quot
for rec in $(< $LIVE_WORK/serverfiles.lst)
do
...
done
IFS=&quot;$savIFS&quot;

Hope This Help, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884

 

[aigles]

With the 'while read' solution, you can assign each column to a variable :
[tt]
while read mode links owner group size time1 time2 time3 name
do
. . .
done < $LIVE_WORK/serverfiles.lst
[/tt]

Jean Pierre.

 

[Ygor]

With either solution, you could assign each column into an array, e.g...

while read rec
do
set -A col -- $rec
echo name is ${col[8]}
done < $LIVE_WORK/serverfiles.lst

 

[dUbbsNIX]

Thanks to everyone. This has solved my problem and in super fast time.

Thanks again,

Dubbs.