Finding what number of record containing x

[bengalliboy]

I got a data file that contains an "x". I need to know what number that is nth record number that got this "x"
what would be the easiest way to do this? I also need to know, if I want to see the "n"th row how to display this? TIA

 

[dickiebird]

try this (untested)
awk '{ $0 ~ /x/ printf("line number %d - Contents %s",NR,$0)}' your_data_file

HTH ;-) Dickie Bird
db@dickiebird.freeserve.co.uk

 

[dickiebird]

Ooops - too much of a hurry !
You need an if()
awk '{ if ($0 ~ /x/) printf("line number %d - Contents %s",NR,$0)}' your_data_file

This will, of course, show ALL rows containing 'x'
HTH ;-)


Dickie Bird
db@dickiebird.freeserve.co.uk

 

[vgersh99]

how 'bout:

awk '/x/ { printf("line number %d - Contents %s",NR,$0)}' your_data_file vlad
+---------------------------+
|#include<disclaimer.h> |
+---------------------------+

 

[dickiebird]

Rats - Vlad is still cheaper ! ;-) Dickie Bird
db@dickiebird.freeserve.co.uk