Finding Information in Multiple Files

[jestrada101]

Hello...
I have the following, which searches within a list a files for anything that starts with 2003 using the cut command.

I'd like for this to give me only the file names that return values that begin with 2003.

Thanks for any recommendations...

for i in BT*
do
echo "${i}"
cut -b76-89 "${i}" | grep ^2003
done

 

[jestrada101]

I figured this out.. and is working for what I need it to do...

Thanks!
JE

for i in BT*
do
cut -b76-89 "${i}" | grep ^2003
result=$?
if [[ ${result} == 0 ]]
then
echo "${i}" >> 2003files
fi

done

 

[jestrada101]

Is there a way to only have "cut" return a single value... once it finds the first 2003, i'd like for it to stop and then check the next file..

thanks!
JE

 

[aigles]

Try something like this :
[tt]
for i BT*
do
grep -l -E '.{75}2003'
done
[/tt]

Jean Pierre.

 

[aigles]

Oops, alittle error , must be read :
[tt]
for i BT*
do
grep -l -E '^.{75}2003'
done
[/tt]


Jean Pierre.

 

[jestrada101]

i get
bash-2.05$ grep -E
grep: illegal option -- E
Usage: grep -hblcnsviw pattern file . . .
bash-2.05$

when trying to use "-E"

 

[aigles]

Use egrep instead of grep -E

Jean Pierre.

 

[PHV]

Try something like this:
for i in BT*
do awk 'substr($0,76,79)==2003{print FILENAME;exit}' $i
done > 2003files

Hope This Help, PH.
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