find numeric character 1

[mdraja]

Hi,

I need to be able to read through a file and highlight all lines that have a numeric character in the 19th position.

Any help greatly appreciated

 

[PHV]

The awk way:
awk 'substr($0,19,1)~[0-9]' /path/to/file
The grep way:
grep -E '^.{19}[0-9]' /path/to/file

Hope This Help, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884

 

[mdraja]

thanks PHV
You have been a legend mate

 

[Ygor]

I think you would get errors unless....
[tt]
grep -E '^.{[red]18[/red]}[0-9]' /path/to/file
[/tt]

 

[Ygor]

Also....
[tt]
awk 'substr($0,19,1)~[red]"[/red][0-9][red]"[/red]' /path/to/file
[/tt]

 

[PHV]

Good catch, Ygor. I'm feeling like a monday morning today.
Will try to do more test before posting.

 

[mdraja]

thanks all

I noticed the 18 when I was applying the grep and I was initially always 1 charachter out ... but the principle got me there in the end

Thanks for all the help