Find and Replace

[upilliappan]

Hi
I have a logfile as follows
******************
timeout=100
users=120
home=/usr/kevin
capacity=222
capacity=666
*******************

I want to grep for the pattern "capacity=" and remove the characters following it.
****************************
timeout=100
users=120
home=/usr/kevin
*****************************

Please help me in writing a script which uses sed command for doing it ]#
Regards
Upilli

 

[feherke]

Hi

sed '/^capacity=/d' /input/file > /output/file

[gray]# or[/gray]

sed -n '/^capacity=/!p' /input/file > /output/file

[gray]# or[/gray]

grep -v "^capacity=" /input/file > /output/file

[gray]# or[/gray]

awk '!/^capacity=/' /input/file > /output/file

[gray]# or[/gray]

awk '/^capacity=/{next}1' /input/file > /output/file

GNU [tt]sed[/tt] supports in-place editing too :

sed -i '/^capacity=/d' /input/file

Feherke.

http://rootshell.be/~feherke/