File classpath

[LuckyKoen]

In my webapplication, there is a directory JavaSource for my java classes and a directory WebContent for my .jsp and .xml files. I want to open one of the xml files in my Action class .

Until now I used the full path (C:/ .../project/WebContent/myXMLFile.xml to open this file. Having this url hardcoded in my java class is not the way I would like to keep it, so I was wondering how I could open this file without having to give a full path. When I just use "myXMLFile.xml", the java class looks on the directory of my editor instead of the web application

 

[venur]

Hi

Try some thing like this is action class

 String xmlFilePath = getServlet().getServletContext().getRealPath("/myXMLFile.xml");

Cheers
Venu

 

[LuckyKoen]

Many thanks, that's exactly what I was looking for.