field seperation problem in awk

[balajipn]

Hi,

I have a unix command "hogs" which gives the formatted output from the "ps -ef" command. The output of this command is given below.

============================================================
14768 5.2 02:54:09 236 root abmon -m 2
5246 0.3 00:40:06 160 root /usr/sbin/syncd 0
12646 0.1 00:13:38 2708 root /usr/sbin/sddsrv
6336 0.1 00:12:34 1260 root dtgreet
============================================================

I would like to extract each line into six fields. For ex, for the first record, following should be the values that I need.

$1 = 14768
$2 = 5.2
$3 = 02:54:09
$4 = 236
$5 = root
$6 = abmon -m 2

Can some one help me?. My $6 variable should contain everything after $6.

Thanks,
Balaji.

 

[feherke]

Hi

If the number on spaces between the sixth and following fields does not count, then you could concatenate them :

awk '{for(i=7;i<=NF;i++)$6=$6FS$i;NF=6}{ [green][i]your code here[/i][/green] }' /input/file

Tested with [tt]gawk[/tt] and [tt]mawk[/tt], should work with [tt]nawk[/tt] too.

Feherke.

http://rootshell.be/~feherke/

 

[PHV]

And what about substr($0,34) ?

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ181-2886