extract two letters from a line 1

[tg2003]

Hello,
I'm a new in this area.

I would like to know how to extract the last two letters from a line, e.g. the line is "ver1.00.23.45" , so I want to put "45" into a variable.

I'm using ksh. Please tell me what commands related (sed?awk?

Thanks in advance!

 

[feherke]

Hi

With [tt]pdksh[/tt] and [tt]bash[/tt], should work with regular [tt]ksh[/tt] too :

v="ver1.00.23.45"
echo ${v##*.}

With some tools :

echo "ver1.00.23.45" | tail -c 3
[gray]# or[/gray]
echo "ver1.00.23.45" | sed 's/.*\(..\)$/\1/'
[gray]# or[/gray]
echo "ver1.00.23.45" | gawk '{print gensub(/.*(..)$/,"\\1","")}'
[gray]# or[/gray]
echo "ver1.00.23.45" | awk '{print substr($0,length($0)-1)}'

Feherke.

http://rootshell.be/~feherke/

 

[Ygor]

Not forgetting...

expr "ver1.00.23.45" : '.*\(..\)'

 

[feherke]

Hi

Cool ! I never noticed that sentence in the man.

Feherke.

http://rootshell.be/~feherke/