Extract number between characters

[jmarkus]

I have a filename like PT.3_BUSHING-212389.csv

The only thing that is consistent is that a "-" comes before the number and a "." comes after.

How can I extract the 212389 to use in a variable.

I have tried

echo "PT.3_BUSHING-212389.csv" | sed -n '/-/,/./p'

thanks,
Jeff

 

[vgersh99]

echo "PT.3_BUSHING-212389.csv" | sed 's/.*-\([0-9][0-9]*\).*/\1/g'

vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+

 

[PHV]

In a ksh compatible shell, you may try something like this:
a="PT.3_BUSHING-212389.csv";a=${a%.*};a=${a##*-};echo "$a"

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ222-2244

 

[jmarkus]

Thanks guys. I ended up using:

number=`echo PT.3_BUSHING-212389.csv | cut -f 2 -d '-' |cut -f 1 -d '.'`

and it worked the way I needed it to.

Jeff