Extract lines between delimiter to file based on first field of record 1

[blarneyme]

Have a text file that contains:

xhost1
line with text
second line with text
third line with text
=======================
zhost2
line with text
second line with text
third line with text
fourth line with text
fifth line with text
======================
zhost3
line with text
second line with text
======================
jail4
line with text
second line with text
third line with text
======================

Want to extract all lines between "=================" and put the contents into a file name ([x|z]host|jail)[N].txt for each host.

Note the host may be "xhost" "zhost" or "jail"

For example:
# cat xhost1.txt
line with text
second line with text
third line with text

#cat zhost2.txt
line with text
second line with text
third line with text
fourth line with text
fifth line with text

awk '
        { RS = "================================="; FS = "\n" }
        ($1 == "^xhost") {print $0}
' myfile > $1.txt

Unfortunately all I get if print to stdout is the hostname (host1) and that is it. If printing to the file ($1.txt) I'm not getting any file.

Thanks

 

[PHV]

awk '/^======/{next}/^([xz]host|jail)/{out=$1".txt";next}{print >out}' myfile

Hope This Helps, PH.
FAQ219-2884
FAQ181-2886

 

[blarneyme]

Perfect. Thank you.