Extract Data From A Variable

[Grizzly521]

Hi Im wondering how to extract data from a variable, maybe using SED or AWK. I have a variable that contains YYYYMMDD, something like var=20091013. Can I extract the year, YYYY, to varY, the month, MM, to varM and the day, DD to varD?

 

[feherke]

Hi

Depends on your shell. Probably the simplest and fastest :

[navy]varY[/navy][teal]=[/teal][green][i]"${var:0:4}"[/i][/green]
[navy]varM[/navy][teal]=[/teal][green][i]"${var:4:2}"[/i][/green]
[navy]varD[/navy][teal]=[/teal][green][i]"${var:6:2}"[/i][/green]

Tested with [tt]bash[/tt] and [tt]mksh[/tt].

Feherke.

http://rootshell.be/~feherke/

 

[PHV]

man expr

Hope This Helps, PH.
FAQ219-2884
FAQ181-2886

 

[Annihilannic]

Here's another way (which may not work on Linux, depending on your shell):

echo $var | sed 's/\(....\)\(..\)\(..\)/\1 \2 \3/' | read varY varM varD

Annihilannic.

 

[SamBones]

I like Anni's solution best, but here's another way in Korn shell...

VAR=20091014

YYYY=${VAR%????}
DD=${VAR#??????}
MM=${VAR%??} ; MM=${MM#????}