exporting variable from a file 2

[joeroe3380]

HI group,

I have an output file with a single row and 24 fields seperated by spaces as shoen below:

000 156 317 441 605 800 156 316 441 605 800 999 00009 15659 31709 44119 60519 80029 15649 31699 44109 60509 80019 99999
i want to export (as an environment variable), each of the column, to be used for further processing.

for eg.export $var1 =000, $var2=156.........$var24=99999;

im trying to do something like beneath ..but without sucess..i'm new to unix..with just a couple of scripts written..

$ awk '{ for(i=1;i<=NF;i++) printf($i)}'< output.dat
000156317441605800156316441605800999000091565931709441196051980029156493169944109605098001999999$
$ export $1= awk '{printf($1)}'< output.dat
/bin/ksh: =: is not an identifier
$ export $1 | awk '{printf($1)}'< Joutput.dat
/bin/ksh: {printf($1)}: is not an identifier

plz provide some advice on how to go abt this.

Thanks in advance!!

 

[stefanwagner]

awk '{ for(i=1;i<=NF;i++) printf("export var"i"="$i"\n")}' < data.raw > varout.sh

will save the variables to a script varout.sh.
You will need to source it:

. varout.sh

or

source varout.sh

afaik you may not force the parent/ the caller of the script, to know these variables.

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[PHV]

Something like this ?
eval $(awk '{printf "export";for(i=1;i<=NF;++i)printf " var%d=%s",i,$i;printf "\n"}' output.dat)

Hope This Helps, PH.
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