exporting shell variable to AWK

[Guest_imported]

I would like to access to my shell variable in this script:
mydate='date | awk '{print $3 $4}''
awk '
{
print $0, $mydate

}' namefile

It does work if I put '$mydate' my variable mydate is taken like a string($mydate) and not a variable containing the date.

 

[vgersh99]

Approach:
1. man awk
2. Read FAQ
3. Read archives


mydate=`date`;
awk -v awkDate=$mydate '{print awkDate $3 $4}'

 

[jramirez]

Don't use date because it shows a lot of strings and the AWK expression doesn´t going to work.
But it works fine with just a string.

 

[flogrr]

Hi asqwertyyt,

Awk cannot deal with shell variables directly,
but you can pass them in as escaped vars and
awk will expand them.


mydate=`date|awk '{printf("%s %s\n", $3,$4) }'`

nawk '
{

print $0", '"$mydate"'"

}' namefile


Hope this is what you need.



flogrr
flogr@yahoo.com