Exiting if conditions arent met

[nogs]

On a script Im running I want it to exit if two commands have no output.
These are the commands;

#LOG ALL USERS IDLE FOR 1 HOUR PLUS;
finger -i | awk '/hour/ && $7 > 0 { print $1 ; }' > /dev/null 2>&1

#LOG ALL USERS IDLE FOR 45 MINUTES PLUS;
finger -i | awk '/minutes/ && $7 > 45 { print $1 ; }' > /dev/null 2>&1

If neither have any output then exit.
If either or both have outout then carry on.
Whats the best way of doing this?

Nogs

 

[bigoldbulldog]

You are removing both stdout and stderr. Try to just close stderr (done below) and moniter stdout with a variable to hold lines of output. As such:

OUTLINES=`
(
#LOG ALL USERS IDLE FOR 1 HOUR PLUS;
finger -i | awk '/hour/ && $7 > 0 { print $1 ; }' 2> /dev/null

#LOG ALL USERS IDLE FOR 45 MINUTES PLUS;
finger -i | awk '/minutes/ && $7 > 45 { print $1 ; }' 2> /dev/null) | wc -l`

if [ ${OUTLINES} -eq 0 ]; then
exit 0
fi

Good luck,
ND

 

[mrn]

use &&

if first runs ok it then runs the second

ls && ps would produce

file2 file2

PID TTY S TIME CMD
2270329 pts/1 I + 0:00.39 -ksh (ksh)
2271159 pts/2 S 0:00.10 -ksh (ksh)

but

dfdfdfdf && ps

would produce an error because the first failed the second wouldn't run.

you can also use || (run second only if first fails)

ls || ps

would only run the ls command

dfdfdfdf || ps

would only run the ps command

you could create 2 scripts, one containing your finger command and a sleep and the other that runs the first again

script1 && script 2

if script1 fails script2 runs


Mike

--
| Mike Nixon
| Unix Admin
|

http://www.instantflashshop.com

----------------------------

 

[aigles]

Hi Nogs,

If you just want to check if there is no user idle for more tan 45 minutes :

finger -fw | awk '$3~/[:d]$/ || $#~/^[0-9]+$/ && $3>45 {exit 1}' | exit 0

If you need the list of users :

IDLE_USERS=$(finger -fw | awk '$3~/[:d]$/ || $#~/^[0-9]+$/ && $3>45')
[ -z "$IDLE_USERS" ] && exit 0 Jean Pierre.