exiting a dos based program?

[FURY]

ok if u making a program that just displays text in a dos window what code do u use say if u wanted a option on a menu for exit?

 

[aphrodita]

You could use switch statement:

...
printf("1: Option\n"
printf("2: Option\n"
printf("3: Option\n"
printf("4: Option\n"
printf("5: Exit \n"

printf("Enter your choice\n"
char option;
scanf("%c",&option);

switch(option)
{
case '5':
printf("You chose to exit, press a button"
option = getch();
exit(0);
...
}
Best Regards,

aphrodita@mail.krovatka.ru {uiuc rules}

http://www.hellforge.org

 

[FURY]

can u tell me why i keep getting this error im really new to c, also im trying to call a function from a switch statement to display another menu can u help

Call to function 'exit' with no prototype in function main

 

[mbaranski]

you need to include the file that exit() is defined in...

make sure you call exit(0) with an integer, and post your code for more help.

Disclaimer:
Beware: Studies have shown that research causes cancer in lab rats.

 

[aphrodita]

You should #include <stdlib.h> {if I'm not wrong}
to use exit function Best Regards,

aphrodita@mail.krovatka.ru {uiuc rules}

http://www.hellforge.org

 

[FURY]

ok u stated &quot;you need to include the file that exit() is defined in...&quot; can u give me an example

 

[aphrodita]

I just gave it in my last response !


#include <stdlib.h> // it must be on before your main function. Best Regards,

aphrodita@mail.krovatka.ru {uiuc rules}

http://www.hellforge.org

 

[mbaranski]

//File main.cpp

#include <stdlib.h>

void main(void){
exit(0);
}

//End file main.cpp

Just like aphrodita said, this is a complete example for you.

Disclaimer:
Beware: Studies have shown that research causes cancer in lab rats.

 

[FURY]

ok thanks

 

[rbobbitt]

Only don't return void from main() and if you're writing C code, make sure you save your files with a .c extension.

Another option is to use return instead of exit():

int main(void)
{
return 0;
}

Russ
bobbitts@hotmail.com

http://home.earthlink.net/~bobbitts

 

[Kapadia]

Hi,
I would like to put some light on use of exit(0) with exit(interger>0). 0 passed to exit(0) means normal termination of a program. Also means that the program has successfully exited its termination whereas exit(1) means some error happened in the execution, and the program has forcefully exited(Abnormal termination).

#include<stdlib.h>
#include<stdio.h>
   void main()
   {
      FILE *fp;
      
      fp = fopen(&quot;myfile.dat&quot;,&quot;r&quot;);
      if(fp==NULL)
      {
          printf(&quot;Unable to open file&quot;);
          exit(1);
      }
      else
      {
          printf(&quot;File openned successfully&quot;);
          exit(0);
      }
    }

Hope this helps in better understanding.

Hemant.

 

[rbobbitt]

another void main()...

To shed a bit more light, the only portable arguments to exit() are 0, EXIT_SUCCESS and EXIT_FAILURE. The C standard leaves any other arguement value, including 1 (which may or may not equal EXIT_FAILURE), undefined.

Russ
bobbitts@hotmail.com

http://home.earthlink.net/~bobbitts