exit status

[yy2]

Hi,

Can anyone tell me why I get the different exit status for the following script execution:

Script A
----------
ksh -c "/proj/prog.exe " 2>>/tmp/run.log 1>/tmp/error.log << !
^M
!
ret_code=$?

Script B
--------
ksh -c "/proj/prog.exe " << !
^M
!
ret_code=$?

Why am I getting different exit status (ret_code) from script A and script B?

The correct return code should be from the program - prog.exe which is 100, but I am getting exit status as 1 in script A ? Why?

I am suppose to use method script A but how to get the correct return code in this case?

 

[yai]

Hi,
what does the ! in lines 3 of both scripts mean? ! in general is the negation operator and, used alone, always returns false. The : (the nop operator) always returns true.

 

[daFranze]

this is a so called here script, you can sub ! by eg HERE

ksh -c "/proj/prog.exe " << HERE
^M
HERE
ret_code=$?

Best Regards, Franz
--
UNIX System Manager from Munich, Germany

 

[yai]

in general, if you mean "HERE" you should say "HERE" or anything meaningful. If (and only if) you mean "not" you should say "!".

 

[daFranze]

yep, full ack! At least it would improve the readability, not sure if it changes the fact, that yy2 get's different returncodes

Best Regards, Franz
--
UNIX System Manager from Munich, Germany

 

[hoinz]

and to answer the original question:
Most probably there is no write permission to the log files /tmp/run.log or /tmp/error.log.