Execute Script on First working day 1

[dbadmin]

Hi,

I need to execute a script on the first working day (M-F) of every month. I tried to configure cron and it doesn't allow me to do this. Is there any way I could do it?

Thanks,
dbadmin.

 

[olded]

Perhaps this shell script might help you out:

http://www.unixreview.com/documents/s=8887/ur0309c/ur0309c.htm

 

[TonyGroves]

You want to execute the job if it's the 1st of the month and a working day, or if it's the 2nd or 3rd and a Monday, right?

You could write a little script (call it 'wd1') like:
[tt]
#!/bin/bash

DOM=`date +%e`
DOW=`date +%a`
exit $( \
[ $DOM -eq 1 -a $DOW != 'Sat' -a $DOW != 'Sun' ] \
|| [ $DOM -le 3 -a $DOW == 'Mon' ]
[/tt]
Then you could set the following command to run every day (or just the 1st 3 days of the month):
[tt]
wd1 && monthlyjobscript
[/tt]

 

[TonyGroves]

Sorry, I forgot a closing bracket at the end of that exit statement:
[tt]
#!/bin/bash

DOM=`date +%e`
DOW=`date +%a`
exit $( \
[ $DOM -eq 1 -a $DOW != 'Sat' -a $DOW != 'Sun' ] \
|| [ $DOM -le 3 -a $DOW == 'Mon' ] )
[/tt]

 

[GrahamBright]

cron should work

1. crontab -e
* * * * 1-5 <absolute path for script>
2. wq!

The fifth file indicates the days of the week 0 to 6 for Sunday to Saturday

 

[SamBones]

GrahamBright, that won't do it. That will cause it to run every weekday in the month, not just the first working day in the month.

 

[dbadmin]

Hi all,

I got the answer from another forum and it goes like this. Schedule the job in cron like this

00 08 1-7 * * x=`date +"%A"` ; [[ $x == "Monday" ]] && Script.sh 2>&1

which will do the trick.

Thanks any way for your valuable time and post. You all are awesome.

Thanks again
dbadmin

 

[hoinz]

dbadmin,

this solution will run your script on the first Monday of every month.
This is not what you asked for in your first post.
Did you change your mind in the meantime?

regards