Execute command through while loop 1

[UsRb]

Hi,

I have following code:

while read f;
do ssh mbu-ibm-hmc1 lssyscfg -r lpar -m Server-9117-MMA-SN655D340 -F name,state --filter lpar_names=$f;
done < 1

1 is a file containing lpar names:
mbu-test-uat-cms-dbms-01
mbu-pci-euroit-dbms-03
mbu-pci-euroit-dbms-02
mbu-pci-test-dbms-01
mbu-pci-euroit-dbms-01
mbu-pci-cms-test-dbms-01
mbu-dev-dbms-01
mbu-prod-cms-app-01
mbu-prod-cms-dbms-01
mbu-prod-pte-dbms-01
mbu-vios-01-02
mbu-vios-01-01

The code should execute one command for one line in file 1 containing lpar_names.
When I execute the code, output is only for the first line in file 1. Why does it stops, where is the catch?

 

[columb]

This one had me stumped for ages when I came across it. The answer is that the ssh command reads stdin and effectively 'eats' the input file. Replace with

while read f;
do ssh [COLOR=#ff0000][b]-n[/b][/color] mbu-ibm-hmc1 lssyscfg -r lpar -m Server-9117-MMA-SN655D340 -F name,state --filter lpar_names=$f;
done < 1

On the internet no one knows you're a dog

Columb Healy

 

[PHV]

Already answered here:
thread822-1277615

Hope This Helps, PH.
FAQ219-2884
FAQ181-2886

 

[UsRb]

Thank you guys a million!