error...cannot convert parameter

[watshamacalit230]

my compiler keeps giving me this error...

C:\Program Files\Microsoft Visual Studio\MyProjects\11\1101x01kt.cpp(25) : error C2664: 'english_number' : cannot convert parameter 1 from 'char [81]' to 'char'
This conversion requires a reinterpret_cast, a C-style cast or function-style cast

what does that mean?

this program is supposed to write the numbers in english( the way we really say them )...from 0-100...i've done it all but i keep getting this error so i've only posted the first half of my code cuz its so long...

heres my code...

#include <stdio.h>

char* english_number( char string ) ;
void get_string( char buffer[], int size ) ;

const int LENGTH = 81 ;

void main( void )
{
	char line[ LENGTH ] ;
	int count ;
	
	printf( &quot;Enter a number  :  &quot; ) ;
	get_string( line, LENGTH ) ;

	printf( &quot;English  :  &quot; ) ;

	for( count = 0 ; line[count] != '\0' ; count++ )
/*error here -->*/	printf( &quot;%s &quot;, english_number( line ) ) ;
}

char* english_number( char string )
{
	if ( string >= '0' && string <= '10' )
	{
		if ( string == '0' )
			return ( &quot;zero&quot; ) ;
		else if ( string == '1' )
			return( &quot;one&quot; ) ;
		else if ( string == '2' )
			return( &quot;two&quot; ) ;
		else if ( string == '3' )
			return( &quot;three&quot; ) ;
		else if ( string == '4' )
			return( &quot;four&quot; ) ;
		else if ( string == '5' )
			return( &quot;five&quot; ) ;
		else if ( string == '6' )
			return( &quot;six&quot; ) ;
		else if ( string == '7' )
			return( &quot;seven&quot; ) ;
		else if ( string == '8' )
			return( &quot;eight&quot; ) ;
		else if ( string == '9' )
			return( &quot;nine&quot; ) ;
		else if ( string == '10' )
			return( &quot;ten&quot; ) ;
	}
}

void get_string( char buffer[], int size )
{
 	char character;
 	int j = 0;		

 	do									/* Get a character until newline or 		*/
 	{									/* we run out of characters.				*/
		character = getchar() ;
		buffer[j] = character ;
		++j;
	}
	while ( character != '\n' && j < size ) ;
	
	while ( character != '\n' )			/* Get rid of extra characters.				*/
		character = getchar() ;

	buffer[j - 1] = '\0' ;				/* Replace newline with the null-byte.		*/
}

 

[qednick]

First off all you should #include <string.h>, then you should return the line from get_string() as a const char*. For completeness, return the string from english_number() as a const char* also. The value passed in as a parameter to english_number() is a single character value yet you are testing it like this:[tt]

else if ( string == '10' )[/tt]

The value of a single character cannot be two characters therefore this parameter should also be a string (const char*) and not a character (char). To test the values you will need to use the strcmp() function - hence the need to #include <string.h>

In saying all this, you may be better off taking the user input as a numerical value and then testing that the number entered is within range. Then pass the number as a parameter to english_number() and return the appropriate string.

^{programmer (prog'ram'er), n A hot-headed, anorak wearing, pimple-faced computer geek.}​