Echoing the last argument ???

[rogsal]

Hi!

I just run into a small problem....
My script takes som parameters and at the end a filename
Is there a simple way to echo that last argument??

I tried different variations of echo "${$#}"
but it doesn't work

all help is useful...
/Roger

ps. my workaround is a loop with a shift statement but I would like a nicer method

 

[columb]

I can't come up with anything better than

for i in $@
do
  fname=$i
done

which isn't that different to your shift loop.

Columb Healy
Living with a seeker after the truth is infinitely preferable to living with one who thinks they've found it.

 

[hoinz]

what about this:

echo $@ | awk '{ print $NF }'

 

[olded]

Hi:

I'm not near a unix terminal, but this should work for the ksh:

lastarg=$(eval echo \$$#)

Regards,

Ed

 

[PHV]

You may try something like this:
eval lastarg=\$$#


Hope This Helps, PH.
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