duplicately named methods in 2 modules how do i differentiate

[damonh78]

Hi,

I am importing 2 modules OrbixTest.pm (resides in /lib/perl) and NamesTest.pm (resides in /Names/lib/perl) using the line:
#!/usr/bin/perl -I/lib/perl -I/Names/lib/perl

I have discovered that both modules contain a package called TestRun and a function called new in the package that I need to use. The implementation of the functions in the 2 packages are different

The function is called in the OrbixTest.pm cause using:
my $testRun = new TestRun($testLog, $autobuild);

and in NamesTest.pm
my $testRun = new TestRun($testLog);

I have just discovered that everytime either of the above lines are called the function in the package in OrbixTest.pm is being invoked.
I need a way to differentiate which module I want to invoke. I was thinking that I can probably use namespaces to do this how would I go about doing this or how should I do it?

Thanks,

John

 

[PaulTEG]

Have you tried OrbixTest::TestRun, and NamesTest::TestRun? This is officially a straw clutch ;-s

Paul
------------------------------------
Spend an hour a week on CPAN, helps cure all known programming ailments ;-)

 

[damonh78]

Unfortunately that doesnt seem to work I can get an error telling me that
:
it's cant locate the object method new via Package NamesTest::TestRun

Cheers anyway,

John

 

[PaulTEG]

How big are the modules, you could rename one of the routines and rename the relevant references, do they do the same thing, or use different paramaters?

Paul
------------------------------------
Spend an hour a week on CPAN, helps cure all known programming ailments ;-)

 

[damonh78]

modules arent too big, but I would then have to change all other scripts that use the module, which I would prefer not too do, so I was hoping that there is a way of differentiating between the two.

 

[mbrooks]

If each module contains constructors do this

my $module1 = OrbixTest->new;
my $module2 = NamesTest->new;

$module1->TestRun();
$module2->TestRun();

M. Brooks

http://mbrooks.info

 

[damonh78]

will try that thanks alot,

John