Drop last character from variable 3

[Autosys]

Hi there -

How do I drop the last character from a variable value. Say I have $VAR=45: I want to stip off the :

Note that the $VAR could have 4 characters for the value.

Cheers in advance!
S

 

[columb]

Try

VAR=$(expr $VAR : "\(.*\).")

Columb Healy

 

[olded]

#!/bin/ksh

VAR=45:
VAR=$(echo "$VAR"|sed 's/:$//g')
echo $VAR

 

[kHz]

# var=45:
# print ${var%%\:*}

 

[SamBones]

Using [tt]sed[/tt] here is overkill. I second kHz's solution. In the Korn shell, the following will delete ANY last character from a variable.

VAR=45:
VAR=${VAR%?}

Hope this helps.

 

[Autosys]

Thanks for all your help! Managed to finished my little script on time because of it.