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Drop Down Problem

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gokeeffe

Programmer
Jan 11, 2005
170
IE
Hi

I have 3 drop down lists depending on what you select in the first drop down, will determine what drop down is displayed, ie when option from dropdown 1 is selected dropdown 2 or 3 will be displayed depending on what option was selected in dropdown 1. Do I need javascript or caqn it be done without. Really coming near to my deadlone and can't figure this out. Also if this helps the dropdowns are pulling from a mysql database.

Tks in advance


------------Dropdown 1---------------


echo'<table align="center">';

if(isset($_POST['secondary_exam_id']))

$_SESSION['secondary_exam_id']=$_POST['secondary_exam_id'];

echo'<tr>
<td colspan="2" class="labelcell">
<label for="secondary_exam_id">* Select Curriculum:</label></td>';

echo'<td colspan="2" class="fieldcell2">

<select name="secondary_exam_id">';

$query_result = mysql_query ('SELECT * FROM secondary_exam_type ORDER BY secondary_exam_id');

while ($row = mysql_fetch_array ($query_result, MYSQL_NUM))
{
if($row[0] == $_SESSION['secondary_exam_id'])
{
$checked = 'selected';
}
else
{
$checked = NULL;
}

echo "<option value=\"$row[0]\" $checked>$row[1]</option>\n";
}

echo'</select></td>';
echo'</tr>';


------------Dropdown 2---------------



if(isset($_POST['junior_subject_id']))

$_SESSION['junior_subject_id']=$_POST['junior_subject_id'];

echo'<tr>
<td colspan="2" class="labelcell">
<label for="junior_subject_id">* Select Junior Subject:</label></td>';

echo'<td colspan="2" class="fieldcell2">

<select name="junior_subject_id">';

$query_result = mysql_query ('SELECT * FROM junior_subjects ORDER BY junior_subject_id');

while ($row = mysql_fetch_array ($query_result, MYSQL_NUM))
{
if($row[0] == $_SESSION['junior_subject_id'])
{
$checked = 'selected';
}
else
{
$checked = NULL;
}

echo "<option value=\"$row[0]\" $checked>$row[1]</option>\n";
}

echo'</select></td>';
echo'</tr>';




------------Dropdown 3---------------



if(isset($_POST['leaving_subject_id']))

$_SESSION['leaving_subject_id']=$_POST['leaving_subject_id'];

echo'<tr>
<td colspan="2" class="labelcell">
<label for="leaving_subject_id">* Select leaving Subject:</label></td>';

echo'<td colspan="2" class="fieldcell2">

<select name="leaving_subject_id">';

$query_result = mysql_query ('SELECT * FROM leaving_subjects ORDER BY leaving_subject_id');

while ($row = mysql_fetch_array ($query_result, MYSQL_NUM))
{
if($row[0] == $_SESSION['leaving_subject_id'])
{
$checked = 'selected';
}
else
{
$checked = NULL;
}

echo "<option value=\"$row[0]\" $checked>$row[1]</option>\n";
}

echo'</select></td>';
echo'</tr>';
 
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