double to int - please help

[nappaji]

This is a samll program

main()
{
double a = 0.01;
doubel b = 0.01;
int i;

i = a/b;

printf ("%d", i);

}


When I print out i, it prints 0 instead of 1. What I suspect is since its a double / double division, there might be a precision problem. How do I conver the output of the division to an integer??? I want i to be declared an integer.

The precision problem might give out an i value of 0.99988 or something like that.

Thanks

 

[Denster]

The only thing I can see wrong with it is that you've spelt double wrong - "doubel". I compiled and ran it with the correct spelling and it was OK!.








Denster

 

[Leibnitz]

To avoid the warning for converting double to int,you can use the cast operator "( )" like this:

#include <stdio.h>
void main()
{
double a = 0.01;
double b = 0.01;
int i;

i = (int)(a/b);

printf (&quot;%d &quot;, i);
}

 

[hnd]

I think that is a precision problem.

To avoid it try:

i=a/b+0.0000001;
hnd
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