Doing a condition with begins and an AND

[MCubitt]

I currently have the following:

if [ "$srcdb" = "$desdb" ]
then
  echo "Start normal"
else
  echo "Start control"
fi

Which works.

However, it should only do the "start normal" of $srcdb=$desdb AND both srcdb and desdb begin with IFS.

Could someone please demonstrate how this may be achieved?

thanks






Applications Support
UK

 

[PHV]

AND both srcdb and desdb begin with IFS
???
Can you please elaborate the context of this test ?

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ222-2244

 

[MCubitt]

Ok, if the value of both variables beging with the literal "IFS" and the two values are different, then do it.. else don't.




Applications Support
UK

 

[PHV]

if [ "`expr substr $srcdb 1 3`" = "IFS" -a "`expr substr $desdb 1 3`" = "IFS" -a "$srcdb" != "$desdb" ]
then
echo "do it"
else
echo "don't"
fi

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ222-2244

 

[MCubitt]

Many thanks, it works!


Can I confirm...

The -a means AND like || means OR?

Why one has to have "$srcdb" != "$desdb" but when looking for the IFS, we use $srcdb (not "$srcdb"). is it because it is already in "" from the "`...`" section?

Thanks


Applications Support
UK

 

[PHV]

The -a means AND like || means OR
-a is inside the brackets ([ ... ]): man test
|| is a shell operator : man yourshell
Why one has to have "$srcdb" != "$desdb" ...
OK, if srcdb or desdb may contains space:
if [ "`expr substr \"$srcdb\" 1 3`" = "IFS" -a "`expr substr \"$desdb\" 1 3`" = "IFS" -a "$srcdb" != "$desdb" ]


Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ222-2244