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Do while, If, select case
- Thread starter Crazier
- Start date
Guest_imported
New member
- Jan 1, 1970
- 0
DIM Board$
FOR row = 1 TO 3
FOR col = 1 TO 3
PRINT Board$(col) + "| _ ";
NEXT col
PRINT "|"
NEXT row
INPUT "If you are the first player please type in X or O for the second player"; Player$
INPUT "Please type in 1 for the 1st position, 2 for the second etc."; position
DO WHILE Player$ <> Q$
IF Player$ = X$ THEN
SELECT CASE position
CASE 1
position = 1
LOCATE 1, 3
PRINT "X"
CASE 2
position = 2
LOCATE 1, 7
PRINT "X"
CASE 3
position = 3
LOCATE 1, 11
PRINT "X"
CASE 4
positon = 3
LOCATE 2, 3
PRINT "X"
CASE 5
position = 4
LOCATE 2, 7
PRINT "X"
CASE 6
position = 5
LOCATE 2, 11
PRINT "X"
CASE 7
position = 6
LOCATE 3, 3
PRINT "X"
CASE 8
position = 7
LOCATE 3, 7
PRINT "X"
CASE ELSE
position = 8
LOCATE 3, 11
PRINT "X"
END SELECT
ELSEIF Player$ = Q$ THEN
END
END IF
IF Player$ = O$ THEN
INPUT "Please type in 1 for the 1st position, 2 for the second etc."; position
SELECT CASE position
CASE 1
position = 1
LOCATE 1, 3
PRINT "O"
CASE 2
position = 2
LOCATE 1, 7
PRINT "O"
CASE 3
position = 3
LOCATE 1, 11
PRINT "O"
CASE 4
positon = 3
LOCATE 2, 3
PRINT "O"
CASE 5
position = 4
LOCATE 2, 7
PRINT "O"
CASE 6
position = 5
LOCATE 2, 11
PRINT "O"
CASE 7
position = 6
LOCATE 3, 3
PRINT "O"
CASE 8
position = 7
LOCATE 3, 7
PRINT "O"
CASE ELSE
position = 8
LOCATE 3, 11
PRINT "O"
END SELECT
ELSEIF Player$ = Q$ THEN
END
END IF
LOOP
FOR row = 1 TO 3
FOR col = 1 TO 3
PRINT Board$(col) + "| _ ";
NEXT col
PRINT "|"
NEXT row
INPUT "If you are the first player please type in X or O for the second player"; Player$
INPUT "Please type in 1 for the 1st position, 2 for the second etc."; position
DO WHILE Player$ <> Q$
IF Player$ = X$ THEN
SELECT CASE position
CASE 1
position = 1
LOCATE 1, 3
PRINT "X"
CASE 2
position = 2
LOCATE 1, 7
PRINT "X"
CASE 3
position = 3
LOCATE 1, 11
PRINT "X"
CASE 4
positon = 3
LOCATE 2, 3
PRINT "X"
CASE 5
position = 4
LOCATE 2, 7
PRINT "X"
CASE 6
position = 5
LOCATE 2, 11
PRINT "X"
CASE 7
position = 6
LOCATE 3, 3
PRINT "X"
CASE 8
position = 7
LOCATE 3, 7
PRINT "X"
CASE ELSE
position = 8
LOCATE 3, 11
PRINT "X"
END SELECT
ELSEIF Player$ = Q$ THEN
END
END IF
IF Player$ = O$ THEN
INPUT "Please type in 1 for the 1st position, 2 for the second etc."; position
SELECT CASE position
CASE 1
position = 1
LOCATE 1, 3
PRINT "O"
CASE 2
position = 2
LOCATE 1, 7
PRINT "O"
CASE 3
position = 3
LOCATE 1, 11
PRINT "O"
CASE 4
positon = 3
LOCATE 2, 3
PRINT "O"
CASE 5
position = 4
LOCATE 2, 7
PRINT "O"
CASE 6
position = 5
LOCATE 2, 11
PRINT "O"
CASE 7
position = 6
LOCATE 3, 3
PRINT "O"
CASE 8
position = 7
LOCATE 3, 7
PRINT "O"
CASE ELSE
position = 8
LOCATE 3, 11
PRINT "O"
END SELECT
ELSEIF Player$ = Q$ THEN
END
END IF
LOOP
- Thread starter
- #3
![[flame]](/data/assets/smilies/flame.gif "[flame] [flame]")
Hey, what do you expect? This person gave you more to go on than what I would have given you.And I would have give you the straight answer:
YES (without any examples!)
Besides, have YOU even tried doing it before posting here? If you have and you are having problems with it, then post your code so that we can all take a look and try to point out what may be wrong. --MiggyD
Never be afraid to try something new. Remember that amateurs built the Ark. Professionals built the Titanic.
- Thread starter
- #5
Yes I did try it first and I was having problems with my program, so I wanted to make sure that you could do the three things together. I try to work out my problems first before I get help and that was all I needed at the time and I thank you for your response.
Crazier,
Your [tt]SELECT CASE[/tt] blocks are not particularly well-structured, and it is not the right structure for the job in the first place. First of all, you are assigning to [tt]position[/tt] the value that it is already known to hold. The first line of each [tt]CASE[/tt] is roughly equivalent to:
[tt]
IF position = 5 THEN LET position = 5
[/tt]
Secondly, if you think of the math for a bit, you can calculate the coordinates to which to [tt]LOCATE[/tt]. Here is one way you could do it:
[tt]
LOCATE (position - 1) \ 3 + 1, ((position - 1) MOD 3) * 4 + 3
[/tt]
Here is why that works: When position is between 1 and 3, you want it to be on line 1, when it is between 4 and 6, you want line 2, and when it is between 7 and 9, you want line 3. The integer division operation '\' throws away the remainder of the division, giving only the integer quotient. Thus, 0 \ 3 = 1 \ 3 = 2 \ 3 = 0; 3 \ 3 = 4 \ 3 = 5 \ 3 = 1; 6 \ 3 = 7 \ 3 = 8 \ 3 = 2. Therefore, by subtracting one from [tt]position[/tt] and dividing it by 3, you get a number that goes up by one each time row changes, as you go through the positions in order. You then simply add to this the desired first row.
As for the other option, the [tt]MOD[/tt] operator returns the remainder that '\' throws away. The following table shows these values, as well as the desired column:
[tt]
x | x MOD 3 | column
---+---------+--------
0 | 0 | 3
1 | 1 | 7
2 | 2 | 11
3 | 0 | 3
4 | 1 | 7
5 | 2 | 11
6 | 0 | 3
7 | 1 | 7
8 | 2 | 11
[/tt]
As you can see, the values line up perfectly
Since the difference between adjacent columns is 4, you multiply the result of the [tt]MOD[/tt] by 4. Then, when the [tt]MOD[/tt] expression returns 0, you want the column to be 3, so you add this on. The column is thus always equal to [tt](x MOD 3) * 4 + 3[/tt].
Finally, the PRINT statement for each [tt]CASE[/tt] always outputs the same value for each of the [tt][color] #000080]SELECT CASE[/color][/tt] blocks. So, you can replace each of the [tt]SELECT CASE[/tt] blocks with the following code, changing the "X" to "O" as appropriate:
[tt]
LOCATE (position - 1) \ 3 + 1, ((position - 1) MOD 3) * 4 + 3
PRINT "X"
[/tt]
Your [tt]SELECT CASE[/tt] blocks are not particularly well-structured, and it is not the right structure for the job in the first place. First of all, you are assigning to [tt]position[/tt] the value that it is already known to hold. The first line of each [tt]CASE[/tt] is roughly equivalent to:
[tt]
IF position = 5 THEN LET position = 5
[/tt]
Secondly, if you think of the math for a bit, you can calculate the coordinates to which to [tt]LOCATE[/tt]. Here is one way you could do it:
[tt]
LOCATE (position - 1) \ 3 + 1, ((position - 1) MOD 3) * 4 + 3
[/tt]
Here is why that works: When position is between 1 and 3, you want it to be on line 1, when it is between 4 and 6, you want line 2, and when it is between 7 and 9, you want line 3. The integer division operation '\' throws away the remainder of the division, giving only the integer quotient. Thus, 0 \ 3 = 1 \ 3 = 2 \ 3 = 0; 3 \ 3 = 4 \ 3 = 5 \ 3 = 1; 6 \ 3 = 7 \ 3 = 8 \ 3 = 2. Therefore, by subtracting one from [tt]position[/tt] and dividing it by 3, you get a number that goes up by one each time row changes, as you go through the positions in order. You then simply add to this the desired first row.
As for the other option, the [tt]MOD[/tt] operator returns the remainder that '\' throws away. The following table shows these values, as well as the desired column:
[tt]
x | x MOD 3 | column
---+---------+--------
0 | 0 | 3
1 | 1 | 7
2 | 2 | 11
3 | 0 | 3
4 | 1 | 7
5 | 2 | 11
6 | 0 | 3
7 | 1 | 7
8 | 2 | 11
[/tt]
As you can see, the values line up perfectly
Since the difference between adjacent columns is 4, you multiply the result of the [tt]MOD[/tt] by 4. Then, when the [tt]MOD[/tt] expression returns 0, you want the column to be 3, so you add this on. The column is thus always equal to [tt](x MOD 3) * 4 + 3[/tt].Finally, the PRINT statement for each [tt]CASE[/tt] always outputs the same value for each of the [tt][color] #000080]SELECT CASE[/color][/tt] blocks. So, you can replace each of the [tt]SELECT CASE[/tt] blocks with the following code, changing the "X" to "O" as appropriate:
[tt]
LOCATE (position - 1) \ 3 + 1, ((position - 1) MOD 3) * 4 + 3
PRINT "X"
[/tt]
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