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displaying ten results per page in perl cgi

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squish20

Programmer
May 25, 2012
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Hi

I'm pretty new to perl and I am currently trying to do an assignment for school which involves us creating a dating website. This requires me to present 10 profiles per page with links to the next and the previous page. This is the subroutine i wrote to handle this:

Perl:
sub browse_ten {
        my $page = 1; # intialise number of pages
        my @users = glob("user_dir/*);
        #entire array of all the user files to be displayed.
        my $pages_required= ceil(($#users)/10); #calculate how many pages to display
        while ($page le $pages_required) {
                my $start = ($page - 1) * 10; # index to begin displaying them
                my $end   = $start + 10; # show 10 results per page
                $end = scalar(@users) if $end > scalar(@users); # cap the end

                # whether to show links
                if ($start > 0) {
                        # Show a Previous link
                        print "<a href=>\"engcupid.cgi?page=" + ($page - 1) + "\">Previous</a>";
                }
                if (scalar(@users) > $end) {
                        # There's more entries after what's being shown
                        print "<a href=>\"engcupid.cgi?page=" + ($page + 1) + "\">Next</a>";
                }

                # Show the range of entries.
                for (my $i = $start; $i < $end; $i++) {
                        my $user_to_show = $users[$i];
                        $profile_filename = "$user_to_show/profile";
                        open $p, "$profile_filename" or die "cannot open $profile_filename: $!\n";
                        if(-r "$user_to_show/image.jpg"){
                                print img({src=>"$user_to_show/image.jpg", width =>150, height=>$150});
                        } else {
                                print img({src=>"blank_profile.jpg", width=>150, height=>150});
                        }
                        $profile = join '<br>', <$p>; $profile .= "<br>";
                close $p;
                print $profile;
                }
                $page = $page+1;



It previously kept giving me the error that it :Can't modify constant item in scalar assignment at ./trial3.cgi line 37, near ""\">Previous</a>";"

I tried to fix that by replacing the '=' with '=>' in the href lines.
It still gives me a syntax error on those lines which i dont quite seem to be able to fix.

Also there are 2 missing braces in the function coz perl is being silly and complains that there are extra curly braces when i put the right number of braces in [mad]

I was hoping someone could help me figure out what's wrong with that statement.
 
Hi

squish20 said:
I tried to fix that by replacing the '=' with '=>' in the href lines.
Huh ? What is a "href line" ?

Anyway, your first syntax error is in the 3[sup]rd[/sup] line, the missing closing double quote ( " ) :
Code:
[b]my[/b] [navy]@users[/navy] [teal]=[/teal] [b]glob[/b][teal]([/teal][green][i]"user_dir/*[highlight]"[/highlight][/i][/green][teal]);[/teal]

Such errors are clearly visible if you use an editor able to highlight the syntax. Please use one. See faq219-5835 for a brief list.

Feherke.
[link feherke.github.com/][/url]
 
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