Displaying Current Date in C program

[Ambatim]

Hello All,

How to display the current date in a C program.
I know that date command in Unix displays the current date. But how to get that in a C variable and print it in a C program

Thanks in advance

Regards
Mallik

 

[dickiebird]

Use the date/time struct tm
ie
long now;
struct tm *tmstruct, *localtime();
time(&now);
tmstruct = localtime(&now);
printf("%02d/%02d/%04d", tmstruct->tm_mday,tmstruct->tm_mon,tmstruct->tm_year);

 

[Ambatim]

Hello Dickiebird,

Thank you for your reply.

What the statement time(&now) means. You are not using it anywhere else in the code.

Thanks

Regards
Mallik

 

[dickiebird]

Sorry - Spurious line
I cut and pasted the code segment from an old program of mine, and left in some unnecessaries
DB

 

[bluenote]

with the tm struct you can use the strftime function to format the output.

#include <stdio.h>
#include <time.h>

time_t t_now;
struct tm *tm_now;

t_now = time(NULL);
tm_now = localtime(&t_now);

char time_buf[50];

strftime(time_buf,50,&quot;%d/%m/%Y %H:%M:%S&quot;,tm_now);

printf(&quot;%s\n&quot;,time_buf);

---- output
25/03/2002 11:44:14
-------------------


bluenote@clorinda.dnsq.org
(excuse my english)

 

[rwb1959]

All kinds of ways (how do you think the "date"
command works?)

Anyway, you also have "asctime()"...

SYNOPSIS
#include <time.h>

char *asctime(const struct tm *timeptr);

DESCRIPTION
The asctime() function converts the broken-down time in the
structure pointed to by timeptr into a string in the form:

Sun Sep 16 01:03:52 1973\n\0