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determining total number of fields in file 4
- Thread starter noiz
- Start date
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1
- #2
This should do it:
awk 'BEGIN{total=0;}{total+=NF;}END{print total;}' file_name
Russ
bobbitts@hotmail.com
awk 'BEGIN{total=0;}{total+=NF;}END{print total;}' file_name
Russ
bobbitts@hotmail.com
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2
- #3
Hi, noiz and rbobbitt!
Awk command that will display the total number of fields in a file, can be like this:
awk '{ sum += NF } END { print sum }' inputfile
Because awk's variables (other than built-ins) are initialized to the null string, by default. This null string has also numerical value zero. So, you can skip BEGIN section. I like this feature of awk and other scripting languages.
KP.
Awk command that will display the total number of fields in a file, can be like this:
awk '{ sum += NF } END { print sum }' inputfile
Because awk's variables (other than built-ins) are initialized to the null string, by default. This null string has also numerical value zero. So, you can skip BEGIN section. I like this feature of awk and other scripting languages.
KP.
Cool. I keep thinking I'm programming in C when I'm using awk ;-) ... Thanks for the tip.
Russ
bobbitts@hotmail.com
Russ
bobbitts@hotmail.com
Of course it depends on what you mean by a field? In you first example the unix command wc -w testfile will do the same thing, and if you want to return just the 12, then you can do wc -w testfile | tr -s " " | cut -d" " -f2 ... (which I guess is just as complicated as using awk!
Greg.
Greg.
Okay. Same idea.
Here is something really ugly. Could someone
show me how to write it entirely in awk?
#!/bin/sh
gen=`ls -l | awk ' { if ($! !~ /^d/) print $9}' > filelist`
$gen || echo $? ; exit 1 > /dev/null
for i in `cat filelist`
do
awk' {tot += NF} END { print tot, FILENAME }' $i
done
This gives you the files in the working directory and a field count the hard way;
and it is totally inelegant.
I am new here so if you have the time I would appreciate it.
Here is something really ugly. Could someone
show me how to write it entirely in awk?
#!/bin/sh
gen=`ls -l | awk ' { if ($! !~ /^d/) print $9}' > filelist`
$gen || echo $? ; exit 1 > /dev/null
for i in `cat filelist`
do
awk' {tot += NF} END { print tot, FILENAME }' $i
done
This gives you the files in the working directory and a field count the hard way;
and it is totally inelegant.
I am new here so if you have the time I would appreciate it.
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1
- #7
- Thread starter
- #8
gregor weertman
Programmer
wc -w file Gregor.Weertman@mailcity.com
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