Delete one character in the front of a variable 1

[pho01]

In a shell script, I used cat, grep and cut to get a number out of a log file.

INCIDENTNUM=`cat $LOGFILE | grep "INCIDENT NUMBER" | cut -d";" -f 2`

INCIDENTNUM returns " 23"
How do I delete an space char in the front so it reads "23" instead of " 23"?
Thanks,

 

[usige]

You could pipe it to sed. eg:

INCIDENTNUM=` ... | sed -e 's/^  *//`

 

[PHV]

Try something like this:

INCIDENTNUM=`awk -F";" '/INCIDENT NUMBER/{printf "%d",$2}'`

Hope This Help
PH.

 

[Annihilannic]

Or typeset -L INCIDENTNUM.

Annihilannic.