Deisplaying XML using XSL

[TomWestcott]

I am trying to print a list of categorys with sub caegorys is they exsist like this

Category
--subcategory1
Category2

This the xml file and xsl file


<table>
<category>
<title>Category1</title>
<parentID>0</parentID>
<categoryID>1</categoryID>
</category>

<category>
<title>Category2</title>
<parentID>0</parentID>
<categoryID>2</categoryID>
</category>

<category>
<title>SubCategory1</title>
<parentID>1</parentID>
<categoryID>3</categoryID>
</category>
</table>


<?xml version='1.0'?>
<xsl:stylesheet xmlns:xsl=&quot;

http://www.w3.org/1999/XSL/Transform&quot;

version=&quot;1.0&quot;>

<xslutput method='xhtml'
doctype-public = &quot;-//W3C//DTD XHTML 1.0 Strict//EN&quot;
doctype-system = &quot;

http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd&quot;

/>

<xsl:template match=&quot;/&quot;>


<table class=&quot;catMenu&quot;>


<thead>
<tr>
<!-- set up the column headings -->
<th>Category</th>
</tr>
</thead>

<tbody>
<!-- add a table row for each non-empty inner record in the XML file -->
<xsl:apply-templates select=&quot;//category[count(*)&gt;0]&quot; />
</tbody>

</table>


</xsl:template>

<xsl:template match=&quot;category&quot;>
<xsl:if test=&quot;parentID &lt; 1&quot;>
<tr>

<td><a><xsl:attribute name=&quot;href&quot;>browse.php?catID=<xsl:value-of select=&quot;categoryID&quot;/></xsl:attribute><xsl:value-of select=&quot;title&quot;/></a></td>

</tr>
<xsl:for-each select=&quot;category/parentID&quot; = &quot;1&quot;>
<tr>
<td>--<xsl:value-of select=&quot;name&quot;/></td>
</tr>
</xsl:for-each>
</xsl:if>
</xsl:template>
</xsl:stylesheet>

As you can see I need help at the for each bit im a newb!

Thank Tom