Date question 3

[stu78]

Hi,

If I am writing an awk script, how do I append the current date a file I am outputting to i.e.

print var > "/tmp/out.log"

I know I can't use
export DATE=`date +%b%d%Y`

as in ksh, what are my options in awk?

stu.

 

[olded]

Stu:

you can get the system date into an awk script by piping into getline:

"date"|getline var

Regards,

Ed

 

[jad]

i had to :

system("date > /tmp/datefile");
getline date < &quot;/tmp/datefile&quot;;
system(&quot;rm /tmp/datefile&quot;);

when i did it ...

 

[stu78]

Thanks Olden,

How would I assign this var,
ie.

"date"|getline var

to the output log?

I've tried
> "/tmp/log_var.log"

this does not work, I believe because of the double quotes.... any ideas?

 

[olded]

Try:

nawk ' {
"date"|getline var

print var >> "log.file"
} '

 

[CaKiwi]

Set the file name by using

fn = "/tmp/log_" var ".log

and write to it with

print ... > fn CaKiwi

 

[jad]

is:

#!/bin/sh

TODAY=`date "+%Y%m%d"`
awk '{<script>}' > /tmp/log_${TODAY}.log

what you're after?

 

[stu78]

In case anyone's interested....

you can do

"date +%b%d%Y"|getline datevar
fn = "/tmp/"datevar

then
> fn

this will stamp the log in a easier to read fashion.

ie

Oct312002

Later,
Stu

 

[bkonline]

Hi stu78:
Try the following:

Date=`date +%d%m%y`
<do your awking here> | outputname.log.$Date
# The above will assign current date to the variable Date, you can call the variable anywhere in your script.
#the output will look like this outputname.log.103102
#(assumming you run it today). ^^^^^^^^^^^^^^^^^^^^^^^^^^
Experience is the Best Teacher
But its' cost is Heavy!
^^^^^^^^^^^^^^^^^^^^^^^^^^