data formatting

[BigDaz]

if i have a 16-bit integer (i.e. 12345) and i want to send it via tcp/ip how can i send it as two 8-bit bytes and not as 5 char bytes (i.e. '1', '2', '3', '4', '5')?

how can i format the integer before sending so that it takes up as little space as possible?

thanks, bigdaz

 

[pansophic]

What language?

For VB try:

Dim byArray(1) As Byte
byArray(0) = Integer16 And &HFF
byArray(1) = (Integer16 And &HFF00) / 16

Send (byArray)

I think that this work, haven't tried it myself. This would reverse the order as well, sending the higher order byte after the lower order byte.

pansophic

 

[BigDaz]

i'm using visual c++

the problem if found (and i hope i'm mistaken)is that using the 'send' function i can only send chars, but want to send a string or array of 16-bit intergers.

thanks, bigdaz

 

[pansophic]

OK, I think that you will get a better answer posting this to one of the C++ forums here, but this MAY work.

byte [1] bArray = new byte [];
bArray[1] = (byte)int16 && 0xff;
bArray[0] = (byte)((int16 && oxff00)/16);

Send((char)bArray);

pansophic

 

[BigDaz]

cheers in the end i used

on the sending side
bArray[0] = 'unsigned int' & 0xff;
bArray[1] = ('unsigned int' >> 8) & 0xff;

on the receiving side
'unsigned int' = bArray[0] + (bArray[1] << 8);

it was easier than i thought.

cheers, bigdaz.

 

[pansophic]

Forgot about the shift operator. Works much better than dividing, expecially with the posibility that the byte may end up being null.

Glad you worked it out!

pansophic