Cutting our part of text from string

[MCubitt]

In UNIX, how can I set a variable to be the value less the 1st 5 chars?

Eg QWERTYUIOP
returns
YUIOP

thanks


Applications Support
UK

 

[MCubitt]

Sorry, I actually want to retain the value

so PART1 = QWERT
and PART2 = YUIOP


Applications Support
UK

 

[PHV]

var="QWERTYUIOP"
PART1=`expr "$var" : '\(.....\).*'`
PART2=`expr "$var" : '.....\(.*\)'`

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ222-2244

 

[MCubitt]

Thanks!


Applications Support
UK

 

[trifo]

or you can use " expr subst "


9. To return the string starting at position 11, for a length of 6 of the
string "Goodnight Ladies", enter:

expr substr "Goodnight Ladies" 11 6

The following is displayed:
Ladies

 

[SamBones]

In the Korn Shell, you can define your variable to only take the left or right five characters. That way you don't have to do any chopping, they will just always accept what you want.

$ typeset -L5 LEFT5="1234567890"
$ print ${LEFT5}
12345
$
$ LEFT5=ABCDEFGHIJK
$ print ${LEFT5}
ABCDE
$
$ typeset -R5 RIGHT5
$ RIGHT5="1234567890"
$ print ${RIGHT5}
67890

Just change the [tt]5[/tt] in the [tt]-L5[/tt] or [tt]-R5[/tt] to another number to get a different size.

Hope this helps.

 

[SamBones]

Oops, I think I read the question wrong. If you want to chop the first five and also keep the rest, for any length variable, you could do this...

$ VAR="ABCDEFGHIJKLMNOPQRSTUVWXYZ"
$ PART2=${VAR#?????}
$ PART1=${VAR%${PART2}}
$ print ${PART1}
ABCDE
$ print ${PART2}
FGHIJKLMNOPQRSTUVWXYZ

And again, this is Korn Shell.

Hope this helps.