Cut Utility help.

[ranjank]

Hi All,

I have got one file which contains variables defined and the PATHS assigned to the respective variables.For e.g

file abc
PROS=x86; export PROS
CONT=/usr/local/ver/1.00; export CONT
PRO=PRS; export PRO

I want to extract the path till /us/local/ver in CONT variable.IS it possible to do with cut utility or is there any other way by which i can do it.Any help on this will be greatly appreciated.

Regards,
RK.

 

[GrahamBright]

see cut -c

eg

# cut -c1-24 t.out
CONT=/usr/local/ver/1.00

 

[ranjank]

Thanks.I tried with this option but it is giving the output for all the three variables.Or i'm doing it in the wrong way.

Rgds,
RK.

 

[PHV]

man awk

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ222-2244

 

[ranjank]

PHV

I need to extract only /usr/local/ver with awk.Can you tell me with example.

Rgds,
RK

 

[KenCunningham]

For the cut example, adjust the characters returned by adjusting 1-24 appropriately. To get only that line, grep for CONT before using the cut.

 

[PHV]

awk 'BEGIN{FS="[=;]"}$1=="CONT"{print $2}' abc

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ222-2244

 

[ranjank]

Thanks a lot PHV.I tried it but it is giving me the whole out out like /usr/local/ver/1.00.How can i extract only /usr/local/ver leaving 1.00.

Rgds,
RK.

 

[PHV]

Try nawk instead of awk.

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ222-2244

 

[ranjank]

Thanks PHV

nawk is not installed in my unix machine.As i'm newbie to shell scripting can u suggest any other way thru which i can achieve my objective.Help on this will be highly appreciated.

Rgds,
RK.

 

[PHV]

awk '/CONT=/{x=$0;sub(".*CONT=","",x);sub(";.*","",x);print x}' abc

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ222-2244

 

[futurelet]

BEGIN{FS="=|/[^/]*$"}
/^CONT/ {print $2}

 

[ranjank]

Thanks PHV

I'm getting the same out put /usr/local/ver/1.00.

Rgds,
RK.

 

[PHV]

Sorry, misread the leaving part:
awk '/CONT=/{x=$0;sub(".*CONT=","",x);sub("/[^/]*","",x);print x}' abc

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ222-2244

 

[ranjank]

I got it.....Thanks a lot to PHV and Futurelet.Also thanks to kencunningham.
This one worked for me.

awk 'BEGIN{FS="=|/[^/]*$"}/^CONT/ {print $2}' abc

Again thanks a lot to every one who contributed to my question.

Rgds,
RK.

 

[motoslide]

This might only work on your sample file, but I get the desired results with:

$more file1
PROS=x86; export PROS
CONT=/usr/local/ver/1.00; export CONT
PRO=PRS;exportPRO
$
$ ./doit3 file1
/usr/local/ver
$
$ cat doit3
dirname `cat $1|grep CONT|awk -F = '{ print $2 '}|awk -F ";" '{ print $1 '}`

 

[motoslide]

This might only work on your sample file, but I get the desired results with:

dirname `cat file1|grep CONT|awk -F = '{ print $2 '}|awk -F ";" '{ print $1 '}`

$cat file1
PROS=x86; export PROS
CONT=/usr/local/ver/1.00; export CONT
PRO=PRS;exportPRO
$

 

[ranjank]

Ya ur right motoslide....I tried ur option also its working fine.thanks a lot.

Rgds,
RK.