Cut piece of a String

[simpson]

I am attempting to cut the first part of a filename out of a variable.

Filename - servername20090201.csv
servername - all characters until 200

what I am attempting to do is this

---------------
i=servername20090201.csv
echo $i | cut -f1 -d"200"
---------------

Obviously this isn't working for me, can someone assist. The servername is not always a constant size so cut -c1-10 is not going to cut it.

Thanks

 

[feherke]

Hi

As I understand, we can count on that "200" as delimiter :

servername="${filename%200*}"

or

servername="$( echo "$filename" | sed 's/200.*//' )"

Feherke.

http://rootshell.be/~feherke/

 

[simpson]

servername="$( echo "$filename" | sed 's/200.*//' )"


THIS WAS PERFECT... Thank you so much.

 

[p5wizard]

And what will your program do next year?


HTH,

p5wizard

 

[p5wizard]

sed:

[tt]servername=$(echo $i|sed 's/[1-9][0-9][0-9][0-9][0-1][0-9][0-3][0-9]\.csv//')[/tt]

ksh:

[tt]servername=${i%[1-9][0-9][0-9][0-9][0-1][0-9][0-3][0-9].csv}[/tt]

REs even allow for dates in the previous millennium...


HTH,

p5wizard

 

[feherke]

Hi

Just two words :

ksh:

[tt]bash[/tt] too.

Feherke.

http://rootshell.be/~feherke/

 

[p5wizard]

Feherke, I'm not yet re-bourne I'm afraid... ;-)
But you are absolutely right!

HTH,

p5wizard

 

[AnotherAlan]

How about this; in KSH.

servername=${servername%%2*}

Delete everything after and including the first occurence of 2.
Should be good for close on a thousand years ;-)

 

[AnotherAlan]

I didn't read the post properly...oops