cut last value of a variable length string 2

[Birbone]

The `df -m /tmp |grep -v Free|awk '{print $4}'` command is the basis for this question.

Since the length of the output can vary between a one to three digit percentage, how can I cut it so just the last character (%) so always striped.

-B

 

[kHz]

# x=$(df -M /tmp |grep -v Free|awk '{print $4}')
# print ${x%%\%*}

 

[Mag0007]

I am not sure what you are asking...

You don't want the % at the end?

if so, do this.


df -m /tmp |grep -v Free|awk '{print $4}' | sed -e 's/%//'

 

[kHz]

The '-m' is not available on AIX, though '-M' is.

 

[Birbone]

Thanks kHz. That did it.

-B

 

[Birbone]

kHz.... here's the -M vs. -m options taken from the AIX 5200-04 man pages.

-m Displays statistics in units of MB blocks. The output values for the file
system statistics would be in floating point numbers as value of each unit in
bytes is significantly high.

-M Displays the mount point information for the file system in the second
column.


-B

 

[Birbone]

Thanks MAG0007, that works better.

-B

 

[kHz]

You can always use file descriptors:

#!/bin/ksh

df -M /tmp |grep -v Free|awk '{print $4}' | exec 3<&0

while read -u3 df; do
        print -r -- "$df"
done

 

[Ogzilal]

Hi,
Just use printf in your awk

df -k /tmp |grep -v Free|awk '{printf "%3d\n", $4}'

Ali