Cut last character of string

[malladisk]

Hi, I need to cut the last character of a string in a shell script.
For example, I do an
$ls *.c
and from the output produced, I need to cut out the last character. Obviously, the string sizes would be different so I can't use "cut".
How can this be done?
Thanks,
Sashi

 

[vijaychin]

ls -1 | awk '{ print substr($0,1,length($0)-1) }'

 

[stefanwagner]

I enjoy to use two revs:

ls *.c | rev | cut -c 2- | rev

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[PHV]

Something like this ?
ls *.c | sed 's!.$!!'

Hope This Helps, PH.
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