Coverting a char pointer to char

[omaduro]

Does anyone know how to convert a char* to char.

 

[adholioshake]

Hi omaduro.

To answer this, it depends on the context. To illustrate each context I can think of I wrote the program below.
Try it out to see what I mean...

#include <stdio.h>
#include <string.h>

int main (void)
{
  char ch = 'A'; // single character.
  char arr[10];  // array of characters.
  char *ptr;     // pointer to character/array.

  strcpy(arr, &quot;Hello!&quot;);
  printf(&quot; ch=%c \n arr=%s \n&quot;, ch, arr);

  ptr = arr;  // Pointer to string.
  printf(&quot; ptr=%s&quot;, ptr);
  ptr = (char *)ch; // Pointer to a char.
  printf(&quot; ptr=%c\n&quot;, ptr);
  ptr = arr;     // Shows how to manipulate chars in
  *(ptr+1) = ch; // an array(string).
  printf(&quot; ptr=%s&quot;, ptr);

  return 0;
}

I suspect that you meant th pointer to a single char, that required a type-cast (to char *) in the example.

Hope that explains it.

Adonai