Copying a Substring of a String 2

tyt2000 · Mar 14, 2005

Hi,

This is my first time using Java code and I'd really appriciate it if someone helped me with this little problem. I have a registration form that has a Java script at the top to validate fields, I did the code for validating blanks and a verify password. There is one piece of code that I need, I want the "email" field to accept only e-mails that end with "@ut.edu". I've searched the net but couldn't find anything helpful. Here is the code for the entire page:

<BASEFONT FACE="Comic Sans MS" COLOR="DarkBlue">
<HTML>
<HEAD>
<SCRIPT language="JavaScript">


</SCRIPT>

<TITLE>Used College Books System - User Registration</TITLE>
</HEAD>
<BODY BGCOLOR="#FFFF80">
<CENTER>
<%
If Request("Update") = "True" Then
Response.Write "<H1>Used College Books System<BR> Update User Registration</H1>"
Else
Response.Write "<H1>Used College Books System<BR> New User Registration</H1>"
End If
%>
</CENTER>
<P>

<%
If Request("Update") = "True" Then
Response.Write "Please change your registration information as listed below<P>"
Else
If Request("NotFound") = "True" Then
Response.Write "<I>We were unable to locate your information. " & _
"Please take the time to register again.</I><P>"
Else
Response.Write "<CENTER>(If you're already registered with us, " & _
"then click the 'Login' link below.)</CENTER><P>"
End If
Response.Write "You only need to register with our system if you want to " & _
"purchase an existing book, or sell your own books " & _
"on these pages. <BR> " & _
"In order to use these services, please take a few minutes " & _
"to complete the form below. Once you have done that, " & _
"you will have full access to the system."
End If
%>

<FORM ACTION="AddUser.asp" NAME="frmUser" METHOD="POST"
onSubmit="return VerifyData()">
<TABLE BORDER=0>
<TR>
<TD WIDTH=20% ROWSPAN=11> </TD>
<TD>E-Mail Address:</TD>
<TD><INPUT TYPE="Text" NAME="email" VALUE="<%= Session("EMailAddress")%>"
SIZE="40"></TD>
</TR>
<TR>
<TD>First Name:</TD>
<TD><INPUT TYPE="Text" NAME="FirstName" VALUE="<%= Session("FirstName")%>"
SIZE="40"></TD>
</TR>
<TR>
<TD>Last Name:</TD>
<TD><INPUT TYPE="Text" NAME="LastName" VALUE="<%= Session("LastName")%>"
SIZE="40"></TD>
</TR>
<TR>
<TD>Phone Number:</TD>
<TD><INPUT TYPE="Text" NAME="PhoneNumber" VALUE="<%= Session("PhoneNumber")%>"
SIZE="40"></TD>
</TR>
<TR>
<TD> <P>Password:</TD>
<TD VALIGN=bottom><INPUT TYPE="Password" NAME="Password"
VALUE="<%= Session("Password") %>" SIZE="40"></TD>
</TR>
<TR>
<TD>Verify Password:</TD>
<TD><INPUT TYPE="Password" NAME="VerifyPassword" SIZE="40"></TD>
</TR>
<TR>
<TD></TD>
<TD ALIGN=CENTER COLSPAN=2><BR>
<INPUT TYPE="Submit" VALUE="Submit Registration">
  <INPUT TYPE="RESET"></TD>
</TR>
</TABLE>
</FORM>

<HR>
<TABLE BORDER=0 WIDTH=100%>
<TR ALIGN=CENTER>
<TD WIDTH=25%><A HREF="BrowseListings.asp">Browse the listings</A></TD>
<TD WIDTH=25%><A HREF="Login.asp">Login</A></TD>
<TD WIDTH=25%>Register</TD>
<TD WIDTH=25%><A HREF="default.asp">Log-Out</A></TD>
</TR>
</TABLE>

</BODY>
</HTML>

Thanks a lot for your time!

- Thamer

BillyRayPreachersSon · Mar 14, 2005

This should work for you:

Code:

<html>
<head>
	<script type="text/javascript">
		var myEmail1 = 'abc@ut.edu';
		var myEmail2 = 'abc@ut.eda';

		checkEmail(myEmail1);
		checkEmail(myEmail2);

		function checkEmail(address) {
			if (address.lastIndexOf('@ut.edu') != address.length - '@ut.edu'.length) alert('Address ' + address + ' is invalid!');
		}
	</script>
</head>
<body></body>
</html>

Hope this helps,
Dan

The answers you get are only as good as the information you give!

bclt · Mar 14, 2005

Hi there,

Code:

 var a =new String(document.frmUser.email.value);
 if ( a.substring(a.length -7,a.length)!="@ut.edu" )
 {
   alert("do not finish with @ut.edu");
   return false;
 }

Ok ?

bclt · Mar 14, 2005

Notice that the number "7" is the number of characters you want to find at the end of the 'email'.

tyt2000 · Mar 14, 2005

Dan,

Thanks a lot for the quick response, it was very helpful. I had to modify it to make it work:

Code:

var myEmail1 = document.frmUser.email.value;     
checkEmail(myEmail1);
        
function checkEmail(address) {
if (address.lastIndexOf('@ut.edu') != address.length - '@ut.edu'.length) alert('Address ' + address + ' is invalid! You must enter a UT E-mail Address');
}

It works, but the problem is that it still redirects me to the next page when I click "ok" on the message box, I want it to stay on the same page so the user can enter a valid e-mail, just like what happens when I click "ok" on the other message boxes that validate the other fields. Any idea how I could make that happen?

Congrats on becoming TipMaster of the Week!

Thanks again,
- Thamer

tyt2000 · Mar 14, 2005

bclt,

Thanks a lot for that piece of code, this one works too, and forces the users to re-enter the e-mail instead of redirecting them to the next page. I really appriciate your help! now I know how it works...

Although I'd still like to know why Dan's piece of code didn't force the user to re-enter the e-mail. I'm trying to learn

Thanks!

- Thamer

BillyRayPreachersSon · Mar 14, 2005

I'd still like to know why Dan's piece of code didn't force the user to re-enter the e-mail.

Because my code was only to show you how to do the verification you asked for. It did not do anything else - I assumed you would integrate the check you asked for yourself.

Hope this clarifies things,
Dan

The answers you get are only as good as the information you give!

tyt2000 · Mar 14, 2005

Hope this clarifies things

Definitely, thanks for the clarification, I should have included more info in my post (after reading your signature, lol).

- Thamer

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Copying a Substring of a String 2

tyt2000

MIS

BillyRayPreachersSon

Programmer

bclt

Programmer

bclt

Programmer

tyt2000

MIS

tyt2000

MIS

BillyRayPreachersSon

Programmer

tyt2000

MIS

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