copy all attributes of an attribute except one

[Guest_imported]

hi. I have the following problem with xslt when doing xml to xml transformations. In some cases I want to copy an element and it's attributes exept one -which should get a fixed value- to the output tree. What I do to achieve this, you can see in this example code snippet:

<xsl:template name=&quot;tname&quot;>
<element_x att1=&quot;{@att1}&quot; att2=&quot;{@att2}&quot; att3=&quot;fixed&quot;/>
</xsl:template>

It works fine. But my question is, whether it is possible somehow, to say in xsl: copy the element and all atrributes to the output, except the attribute, of name att3 and give a fixed value to it. (This is because not all of my &quot;element_x&quot; elements have the same attributes, and because everytime i add a new feature and therefore add a new attribute to element_x i have to search and replace in all my xsl which works with element_x)

(sorry for my bad english and thanks in advance)

 

[MrTom]

<xsl:for-each select=&quot;@*&quot;>
<xsl:copy/>
</xsl:for-each>

this would copy all the attributes from the current node. you might be able to use

<xsl:for-each select=&quot;@*[local-name()!=@att3]>

but i'm guessing here.

 

[Guest_imported]

Thanks for Your answer,

This worked:

<xsl:template match=&quot;element_x&quot;>
<element_x>
<xsl:for-each select=&quot;@*&quot;>
<xsl:choose>
<xsl:when test=&quot;not(local-name()='att3')&quot;>
<xsl:copy/>
</xsl:when>
<xsltherwise>
<xsl:attribute name=&quot;{name()}&quot;>fixed</xsl:attribute>
</xsltherwise>
</xsl:choose>
</xsl:for-each>
</element_x>
<xsl:apply-templates/>
</xsl:template>

I only hope that i won't receive those &quot;cannot set attribute after child has been added&quot;-errors later on...