Converting epoch seconds to readable date format 2

[vivek1712]

Hi ,


Can anybody help me with a shell or perl script that converts epoch seconds into dd/mm/yy format. My purpose is to write a script that will generate a mail to the user for changing his password as per the maxage setting. For this I need to read the lastupdate field in /etc/security/passwd. For checking the lastupdate field I'm using pwdadm -q $usernm , my OS is AIX 4.3.

Thanx in advance .

Best Regards,
vivek

 

[cruel]

If possible, could you post what the "epoch seconds" look like? My suspicion is either AIX has some utilities to convert it (but I do not know) or you need to develop some utilities yourself, which is not that hard. But post the seconds data and let us see what is doable

 

[Ygor]

Assuming epoch seconds is what you get from perl using print time();

Create a script which accepts epoch seconds as the only argument and returns date and time, eg:

#!/usr/bin/perl
($sec,$min,$hour,$mday,$mon, $year,$wday,$yday,$isdst) = localtime(shift);
$mon++;
$year += 1900;
printf "%02d-%02d-%04d %02d:%02d:%02d\n",$mday,$mon,$year,$hour,$min,$sec;

Tested...
$ convert.pl 1051545709
28-04-2003 17:01:49

 

[vivek1712]

Thanx Ygor for ur script. Cruel I think u have seen the epoch seconds example from ygor's script.

I've done the conversion in the undermentioned way :
Eg : perl -e 'print scalar localtime(1066253412) , "\n";'

Best Regards,
vivek

 

[gamerland]

Ygor,
Please add your solutions to the faq. Both (perl and non-perl) are clean and clear.

-Mike