Phil00001
IS-IT--Management
- May 24, 2012
- 6
I have a number value of 6.1 Hours which I would like to display as 6:06 (6 HRS 6 MINS)
Date In Out Hours(decimal)
Sat 14 Jul 05:52: 11:58: 6.10
Formula used to get 6.1 Hours
(((hour({Clock_On_Clock_Off.Actual_Date_Off})*60)+minute({Clock_On_Clock_Off.Actual_Date_Off}))
-((hour({Clock_On_Clock_Off.Actual_Date_On})*60)+minute({Clock_On_Clock_Off.Actual_Date_On})))/60
Using Crystal 2008 with SQL and Windows XP
Date In Out Hours(decimal)
Sat 14 Jul 05:52: 11:58: 6.10
Formula used to get 6.1 Hours
(((hour({Clock_On_Clock_Off.Actual_Date_Off})*60)+minute({Clock_On_Clock_Off.Actual_Date_Off}))
-((hour({Clock_On_Clock_Off.Actual_Date_On})*60)+minute({Clock_On_Clock_Off.Actual_Date_On})))/60
Using Crystal 2008 with SQL and Windows XP