convert hex base16 to integer 2

[AlbertAguirre]

How can i do this with awk?

 

[PHV]

You may use this function:
function hex2dec(h ,i,x,v){
h=tolower(h);sub(/^0x/,"",h)
for(i=1;i<=length(h);++i){
x=index("0123456789abcdef",substr(h,i,1))
if(!x)return"NaN"
v=(16*v)+x-1
}
return v
}


Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ181-2886

 

[Annihilannic]

In GNU awk the strtonum() function will do the conversion for you if the string is prefixed by a "0x".

[tt]$ awk 'BEGIN {x="0xa"; print strtonum(x)}'
10
$[/tt]

Annihilannic.

 

[bigoldbulldog]

GNU awk also knows the 0xN syntax, i.e. no quotes.

$ awk 'BEGIN{printf("%d\n", 0x13)}'
19
$ awk 'BEGIN{printf("%d\n", "0x13")}'
0
$ awk 'BEGIN{printf("%d\n", strtonum("0x13"))}'
19

Cheers,
ND