convert FSO path to HTTP path 1

[rubychyld]

I am reading a folder of files off the web box and would like to make make these files links. Is there a method or function that will convert the FSO path to the HTTP path??

convert this FSO:
C:\Inetpub\

http://wwwroot\intranet\products\Auto

Lease Application.pdf

to this HTTP:

http://www.cars.com/intranet/products/Auto

Lease Application.pdf

Liz Catch the vigorous horse of your mind!

 

[lobstah]

do you need the absolute URL or will a relative link work?

 

[rubychyld]

either the absolute or the relative would be fine
I could concatonate the relative with Request.ServerVariables("SERVER_NAME&quot or something right?

I suppose I could just replace the first part of the string with the http: info, but I am actually reading from more than a few different locations and this would be a long case statement.

thanks for any help.
Liz Catch the vigorous horse of your mind!

 

[Swany]

' / is c:\inetpub\[URL unfurl="true"]wwwroot[/URL] in this example
strRootWeb = server.mappath("/")

'the filename would come from an FSO, but we'll hard
'code it for this example
strFilename = "c:\inetpub\[URL unfurl="true"]wwwroot\intranet\product\auto.pdf"[/URL]

'remove the base path from the filename
strFilename = right(strFilename, len(strFileName) - len(strRootWeb))

'we should have \intranet\product\auto.pdf as strFilename
strFilename = replace(strFilename, "\", "/")

'we should have /intranet/product/auto.pdf as strFilename

URL = "[URL unfurl="true"]http://"[/URL] & request.servervariables("SERVER_NAME") & strFilename

.
.. Eat, think and be merry .
... ....................... .

 

[Guest_imported]

I would make constants of specific portions pertaining to your system / web ie

Const strSysWebRoot = "C:\Inetpub\

http://wwwroot"

Const strDomainName = "

http://www.cars.com"

etc... then just

strURL = Replace(strPath, strSysWebRoot, "

http://"

& strDomainName)

strURL = Replace(strURL, "\", "/&quot