The answer can only be approximate because months are not all the same. One way might be to calculate based on some arbitrary date. Based on 0 (nominally 31/12/1899), and ignoring leap years, this will do it (assuming your value of 1.95 is in cell A1):
[tt][blue]=DATEDIF(0,A1*365,"m") & " months, " & DATEDIF(0,A1*365,"md") & " days"[/blue][/tt]
Based on the current date:
[tt][blue]=DATEDIF(TODAY(),TODAY()+A1*365,"m") & " months, " & DATEDIF(TODAY(),TODAY()+A1*365,"md") & " days"[/blue][/tt]
Adding an extra day for every four years is a crude way to account for leap years but this will do that:
[tt][blue]=DATEDIF(TODAY(),TODAY()+A1*365+ROUNDDOWN(A1/4,0),"m") & " months, " & DATEDIF(TODAY(),TODAY()+A1*365+ROUNDDOWN(A1/4,0),"md") & " days"[/blue][/tt]
No doubt the Excel experts will have smarter answers
Enjoy,
Tony
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