content of element equals to the name of an external file, how?

[starfish88]

Hi all, if I want the xsl stylesheet to output an xml file that contains an element, which its content is the name of another file in the very same folder/location, does xslt have a way to do so, or I will need to embed some other scripting languages, such as javascript?

Thank you.


Will

 

[JontyMC]

Something like:

<xsl:variable name="myDoc">
  <xsl:value-of select="document('theDoc.xml')/theElement"/>
</xsl:variable>
<xsl:value-of select="document($myDoc)"/>

Jon

"Asteroids do not concern me, Admiral. I want that ship, not excuses.