conditional form variable

[Diggum1]

I know this should be simple, but I just started php. I have a form that will submit an email. The company name will be set by a selection from a drop down (with values of Company1,Company2,Company3). What I have below always returns Company3, regardless of which option I select from the drop down.

Any ideas?
Thanks
RK

$name = $_POST["name"];
$title = $_POST["title"];
$phone = $_POST["phone"];
$fax = $_POST["fax"];
$email = $_POST["email"];
$company = $_POST["company"];


if($company='Company1')
$company="Company1\n10 First Ave\nChicago, IL";
if($company='Company2')
$company="Company2\n10 Second Ave\nChicago, IL";
if($company='Company3')
$company="Company3\n10 Third Ave\nChicago, IL";

 

[vacunita]

Your Ifs aren't right. in PHP you need two or more = signs to make a comparison, one = sign is an assignment.

What you are actually doing is assigning the value of "company X" to the $company variable and then checking if it was correctly assigned. and since the assignment is always correct, it returns true. Meaning it goes through the 3 conditionals overwriting the value of the $company variable each time,


Try this instead:



if($company[red]==[/red]'Company1')
    $company="Company1\n10 First Ave\nChicago, IL";
if($company'[red]==[/red]Company2')
    $company="Company2\n10 Second Ave\nChicago, IL";
if($company[red]==[/red]'Company3')
    $company="Company3\n10 Third Ave\nChicago, IL"; [\code]

----------------------------------
Ignorance is not necessarily Bliss, case in point:
Unknown has caused an Unknown Error on Unknown and must be shutdown to prevent damage to Unknown.

 

[Diggum1]

ah great, thanks!

 

[Diggum1]

Thanks for the explanation, it works great.

 

[vacunita]

No problem. Glad it worked

----------------------------------
Ignorance is not necessarily Bliss, case in point:
Unknown has caused an Unknown Error on Unknown and must be shutdown to prevent damage to Unknown.