compareTo() HELP!

[ilovelinux2006]

Hey everyone,

Ive been working on this for hours!
I have three variables: a, b, c


I am suppose to use a.compareTo(b)

Here is the function:

public int compareTo(Number t){
if(t.getNumber() > this.getNumber()){
return 1;
}else if(t.getNumber() < this.getNumber()){
return -1;
}else{
return 0;
}
}

I have been working many many many hours on trying to get the middle number!!!!!!!!!! I found how to get the two largest and smallest numbers with the compareTo() function:

// Returns the smallest of the 3 Numbers:

if(b.compareTo(a) <= 0 && c.compareTo(a) <=0){

System.out.print(a);
}else if(a.compareTo(b) <=0 && c.compareTo(b) <=0){
System.out.print(b);
}else{
System.out.print(c);
}

// Returns the largest of the 3 Numbers: (I just changed the < to >)

if(b.compareTo(a) >= 0 && c.compareTo(a) >=0){

System.out.print(a);
}else if(a.compareTo(b) >=0 && c.compareTo(b) >=0){
System.out.print(b);
}else{
System.out.print(c);
}


Please help me, this is making me go crazy!

 

[cpjust]

Sort the numbers, then go to the middle of the array.

 

[timw]

I am suppose to use a.compareTo(b)

Forgive me if I'm wrong, but that phrase makes it sound like this is a homework assignment or something. Is It?

Tim

 

[Diancecht]

You got the big one, you got the smaller one: the middle one is the one left

Cheers,
Dian

 

[chrissie1]

left of the middle or left of the right one. Can't be left of the left since there are only three elements.

Christiaan Baes
Belgium

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