compare hex variable to certain value

[EfratS]

Hello,

I'm trying to run the following code:
$found = 0;
$posCount = 0;
while (!($found)){
$b = substr($callBuf, $posCount, 24);
$data = unpack('H24',$b);
if ($data == "0000001d0000000700000001"){
$found = 1;
}
else{
++$posCount;
}
}

$callBuf contains binary data that were read from file,
and the code above suppose to find the position of "0000001d0000000700000001" in $callBuf.
if I print the $data variable I can see that in certain iteration it holds the needed value, but from some reason the comparison statement doesn't "catch" it!

 

[duncdude]

eq NOT ==


Kind Regards
Duncan

 

[EfratS]

tried this also...doesn't work.

 

[ishnid]

As far as I can tell, you're only actually comparing strings, so there's no need for the unpack. Just compare $b (which should really be called something else, incidentally, since it's a special variable for use in the sort() function) to your binary string, using `eq', as duncdude suggested.

 

[duncdude]

I reckon ish is right - what is the string before you unpack it?


Kind Regards
Duncan